Longest word with letters in reverse alphabetical order: punctoschmidtella (17) and spoon-feed (9 letters) Number with letters in reverse alphabetical order: one Number with letters in alphabetical order: forty However, the longest English words with letters in alphabetical order, containing 7 letters are: beefily, billowy. In medicine, an aegilops is an abscess or ulcer in the outer or inner corner of the eye. Technically, this is a Latin term for North American and Eurasian plants in the grass family, Poaceae (generally known as goatgrasses), that are the wild ancestor of modern domestic wheat. The longest word with letters in alphabetical order is Aegilops (8 letters). There are many words with their letters in alphabetical order that contain 6 letters: abhors, accent, access, almost, biopsy, billow, chintz, effort. The word ace contains 3 letters in alphabetical order. Awesome, IDK how I didn't come up with this, my deepest of gratitude.Although the Oxford English Dictionary defines more than 750,000 English words, there are only about 860 words that have their letters arranged in alphabetical order. These are known as abecedarian words (from the Latin word, acededarius, meaning “alphabetical”).Įxcluding the word “a”, the shortest words with letters in alphabetical order, containing only 2 letters, are: am, an, be, is, it, no. However if the variable isn't set to n throughout the loop, it will return as y at the end, which will allow the script to classify the word as one which is spelt in alphabetical order. Upon sensing this, the script above will set the true? variable to n. If a word had the letter B, and the letter after that was A, # item (A) of list would be smaller than that of # item (B) of list. The script above compares a letter with the letter after that, to see if they are in alphebatical order. # item (B) of list would give me 2, and so on. So basically, # item (A) of list would give me 1, since item 1 in the alphabet list is the letter a. define check (word) set to set to repeat (length of ((word) - ) change by (1) if (# item (letter (counter) of (word) ) of :: list) > then set to end end if then add (word) to else word not in alphebatical order ::grey end The “# item () of list” block reports the number of the item in a list that matches the given input. And so on …you can then use the script below. MasterofTheBrick wrote:Assuming that the pre-set list with alphabets is as shown below: 1. define check (word) set to set to repeat ((length of (word)) - (1)) change by (1) if (# item (letter (counter) of (word) ) of :: list) > then set to end end if then add (word) to else word not in alphebatical order ::grey end The “# item () of list” block reports the number of the item in a list that matches the given input. Assuming that the pre-set list with alphabets is as shown below: 1.
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